Java練習(xí)——編寫一個應(yīng)用程序求滿足1+2！+3！+……+n！<=9995的最大整數(shù)n。
package program;
public class Integer {
public static void main (String args[]) {
int sum = 0;
int n = 1;
while(sum<=9995)
{? ?
int s = 1;
for(int i=1;i<=n;i++)
{?
s*=i;
}
n++;
sum = sum+s;
}
n=n-2;
System.out.printf("求滿足1+2！+3！+……+n！<=9995的最大整數(shù)n為:%d",n);
}
}
標簽：
